TSHS Elite Math Circle

𝘼𝙧𝙚 𝙮𝙤𝙪 𝙍𝙀𝘼𝘿𝙔, 𝙎𝙘𝙞𝙚𝙣𝙩𝙞𝙖𝙣𝙨?! 👀✨

Get ready to step into an exciting celebration of Math Month, where numbers come alive and challenges turn into opportunities to grow! 🎉🔢 A fun and engaging lineup of activities awaits, designed to sharpen your skills, boost your confidence, and spark your love for Mathematics. 🧠💡

From mind-twisting puzzles 🧩 and strategic challenges ✖️ to interactive games and thrilling competitions 📊, this month proves that Math is more than solving equations. It is about thinking creatively, working together, and enjoying the process of learning. Every activity is a chance to test your limits and discover what you are capable of. 🌟

Whether you are a passionate problem-solver ❤️➕ or someone eager to try something new 💪📐, there is an event prepared just for you. So bring your focus, trust your skills, and be ready to learn, compete, and have fun alongside your fellow Scientians. ✏️🧮

Do not miss this chance to be part of an unforgettable Math Month experience. Join the activities, take the challenge, and let the excitement begin! 📊💙

(Further details about the activities will be posted soon.)

A round of applause to the Senior High School students of Taguig Science High School who demonstrated their excellence in Mathematics in the recent International Kangaroo Mathematics Competition held on March 23, 2024.

Congratulations to all the awardees!🎉

Let us recognize the Junior High School students of Taguig Science High School who showcased their Mathematics skills in the recent International Kangaroo Mathematics Competition held on March 23, 2024.

Congratulations to all the awardees!🎉

𝗧𝗛𝗘 𝗙𝗜𝗥𝗦𝗧 𝗢𝗡𝗘 [𝗗𝗔𝗬 𝟯] 𝗦𝗢𝗟𝗨𝗧𝗜𝗢𝗡

PROBLEM: In a farm with some hens and pigs, there are 143 combined heads and 366 combined legs of said animals. How many legs will there be if you doubled the amount of chickens and halved the amount of pigs?

Let x be the number of chickens, and y be the number of pigs
since a chicken has 2 legs while a pig has 2, we could say that 2x + 4y = 366. We could make the same reasoning for the heads, making the equation x + y = 143

2x + 4y = 366
x + y = 143

We need to leave only one variable to find its value. To start, we can multiply the second equation by -2, giving us -2x - 2y = -286
2x + 4y = 366
-2x - 2y = -286

We could now combine both equations, leaving us with 2y = 80, which means y, the number of pigs, is 40.

we can substitute the value of y to either equations to find the value of x.

x + 40 = 143
x = 143 - 40
x = 103

There are 40 pigs and 103 chickens.

Now, to find how many legs there will be if we were to double the amount of chickens and halve the amount of pigs, we could use the equation:

2((2)(103)) + 4 ((1/2)(40)) = total legs
2(206) + 4(20) = total legs
412 + 80 = total legs
492 = total legs

Congratulations again to Lance T. De Ado of 8-Fleming, our third winner!