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PUZZLE 36
DIGITS AND CUBES
My Professor recently asked his young friends to find all those five-figure squares such that the number formed by the first two figures added to that formed by the last two figures should equal a cube. Thus with the square of 141, which is 19,881, if we add 19 and 81 together we get 100, which is a square but unfortunately not a cube. How many solutions are there altogether?
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