Mathematics solver by Mexcocity

STEPS USING FACTORING BY GROUPING



x2−4x−5=0

To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as x2+ax+bx−5. To find a and b, set up a system to be solved.

a+b=−4ab=1(−5)=−5

Since ab is negative, aand b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. The only such pair is the system solution.

a=−5b=1

Rewrite x2−4x−5 as (x2−5x)+(x−5).

(x2−5x)+(x−5)

Factor out x in x2−5x.

x(x−5)+x−5

Factor out common term x−5 by using distributive property.

(x−5)(x+1)

To find equation solutions, solve x−5=0 and x+1=0.

x=5x=−1

13/9√5
Solution
13/9√5 × 9√5/9√5
117√5/81×5
=117√5/405

Any question

Solve the inquality
[(5x-1)/3]-(1/2x)≤8+x